Arduino Map: How to map a value from one range to another. It is a useful function but it may not do what you expect! Find out here why it may go wrong and how to use it correctly.

Arduino map

• Maps one range of values to another.
  
  
• It should work the way you think...but it does not!
  
  
• You may find your output range squashed up at one end!
  
  
• Find out why that is so.
  
  
• Also find out what to do about it!
  

Why it may not work exactly the way you think it does! The map function is intended to change one range of values into another range of values and a common use is to read an analogue input (10 bits long, so values range from 0 to 1023) and change the output to a byte so the output would be from 0 to 255.

You would then write the following code

Everything is fine 0 maps to 0, and 1023 maps to 255...

...with an even distribution (really?????).

The map() function is useful but it has a secret hiding within. Its easy enough to use (or so you think) until you look a bit deeper inside. An even distribution is what you want but does it really do that?

Testing Arduino Map

Lets write a sketch to test out exactly what it does

void setup() {

  Serial.begin(9600);

  for (int adc = 0; adc < 1024; adc++) {

    int mapped = map(adc, 0, 1023, 0, 255);
    Serial.print(adc);
    Serial.print(',');
    Serial.println(mapped);
  }
}

void loop() {
}

The problem is the final output value has only 1 input for one output i.e. 1023 results in 255, while 1019~1022 results in 254 as output. What you really want is an even spread of values across the whole range.

To get to this point some of the other outputs must have had 5 values as inputs (you can see that for adc values 0~4 - all 5 inputs result in output of a zero.

Sketch to check Arduino map distribution

This sketch increases the value in bins array every time map returns a value - so each bins[] holds the number of times an output was created.

#define SAMPLES 1024
#define OUTPUTS 256

int bins[OUTPUTS];
const int binsize = (SAMPLES-1)/(OUTPUTS-1);

void setup() {

  Serial.begin(9600);
  Serial.println("Arduino map output distribution");
  Serial.print("Bin size: ");
  Serial.println(binsize);

  // Initialise bins
  for (int i = 0; i < OUTPUTS; i++) bins[i]=0;

  for (int adc = 0; adc < SAMPLES; adc++) {
    int mapped = map(adc, 0, SAMPLES-1, 0, OUTPUTS-1);
    bins[mapped] +=1;
  }

  for(int i=0;i<OUTPUTS;i++) {
    Serial.print("Bin: ");
    Serial.print(i);
    Serial.print(" count ");
    Serial.print(bins[i]);

    // Show bin distribution error
    if ((bins[i] != binsize)) {
      Serial.println(" ***") ;
    } else Serial.println();

  }

  // Find wrong bin count
  for(int i=0;i<OUTPUTS;i++) {
    if (bins[i]!=binsize) {
      Serial.print("Bin error: ");
      Serial.println(i);
    }
  }
}

void loop() {
}

The last part of the output shows four bins with wrong values :

Bin: 253 count 4
Bin: 254 count 4
Bin: 255 count 1 ***
Bin error: 0
Bin error: 85
Bin error: 170
Bin error: 255

So why the error for Arduino map?

The arduino map() reference has this to say:

"As previously mentioned, the map() function uses integer math. So fractions might get suppressed due to this. For example, fractions like 3/2, 4/3, 5/4 will all be returned as 1 from the map() function, despite their different actual values. So if your project requires precise calculations (e.g. voltage accurate to 3 decimal places), please consider avoiding map() and implementing the calculations manually in your code yourself."

The problem is that the upper value of 1023 is not exactly divisble by 255 so you get a slight error. So it is a fraction that is suppressed.

The code for the function is:

long map(long x, long in_min, long in_max, long out_min, long out_max) {
   return (x - in_min) * (out_max - out_min) / (in_max - in_min) + out_min;
}

The calculations are

0 *255/1023 = 0
1 *255/1023 = 0
2 *255/1023 = 0
3 *255/1023 = 0
4 *255/1023 = 0
5 *255/1023 = 1

1022 * 255/1023 = 254
1023 * 255/1023 = 255 

These match the Arduino outputs.

Looking at a simpler output

The problem becomes even more apparent.

if you map 1023 to the output range 0 to 7 the problem becomes even more apparent.

Change the code in the previous sketch redefining 'OUTPUTS' as 8.

The output then becomes:

Arduino map output distribution
Bin size: 146
Bin: 0 count 147 ***
Bin: 1 count 146
Bin: 2 count 146
Bin: 3 count 146
Bin: 4 count 146
Bin: 5 count 146
Bin: 6 count 146
Bin: 7 count 1 ***
Bin error: 0
Bin error: 7

If you tried to map an ADC input using a potentiometer to control an 8 LED bargraph the only time the last LED would light is when the input is 1023!

To fix it make the values a multiple of a power of 2 so the fraction is not suppressed.

Note: For different ranges the difference between max and min must be a power of 2.

The following program uses power of 2 values as input and shows the corrected output.

//#define NUM_SAMPLES 1024 // Must be a power of 2 (Range 0-1023)
//#define NUM_OUTPUTS 256  // Must be a power of 2 (Range 0-255)

#define NUM_SAMPLES 1024 // Must be a power of 2 (Range 0-1023)
#define NUM_OUTPUTS 8    // Must be a power of 2 (Range 0-7)

#define NUM_BINS (NUM_OUTPUTS)

int bins[NUM_BINS];
const int binsize = (NUM_SAMPLES)/(NUM_OUTPUTS);

void setup() {

  Serial.begin(9600);
  Serial.println("Arduino map output distribution");
  Serial.print("Bin size: ");
  Serial.println(binsize);

  // Initialise bins
  for (int i = 0; i < NUM_BINS; i++) bins[i]=0;

  for (int adc = 0; adc < NUM_SAMPLES; adc++) {
    int mapped = map(adc, 0, NUM_SAMPLES, 0, NUM_OUTPUTS);
    bins[mapped] +=1;
  }

  for(int i=0;i< NUM_BINS;i++) {
    Serial.print("Bin: ");
    Serial.print(i);
    Serial.print(" count ");
    Serial.print(bins[i]);

    // Show bin distribution error
    if ((bins[i] != binsize)) {
      Serial.println(" ***") ;
    } else Serial.println();

  }

  // Find wrong bin count
  for(int i=0;i< NUM_BINS;i++) {
    if (bins[i]!=binsize) {
      Serial.print("Bin error: ");
      Serial.println(i);
    }
  }
}

void loop() {
}

Output results: for NUM_SAMPLES = 1024, NUM_OUTPUTS = 8

Arduino map output distribution
Bin size: 128
Bin: 0 count 128
Bin: 1 count 128
Bin: 2 count 128
Bin: 3 count 128
Bin: 4 count 128
Bin: 5 count 128
Bin: 6 count 128
Bin: 7 count 128

Note: The first example is also corrected with an even spread of 4 input values per output.

Another example

Here's another example using random samples and outputs i.e. non-power of 2 values.

#define SAMPLES 1976
#define OUTPUTS 153

Here 1976/153 = 12.91 and each bin has 13 values in it except the last that has one. So the algorithm gets it approximately right.

Bin: 0 count 13 ***
Bin: 1 count 13 ***
Bin: 2 count 13 ***
Bin: 3 count 13 ***
Bin: 4 count 13 ***
Bin: 5 count 13 ***
Bin: 6 count 13 ***
Bin: 7 count 13 ***

Bin: 145 count 13 ***
Bin: 146 count 13 ***
Bin: 147 count 13 ***
Bin: 148 count 13 ***
Bin: 149 count 13 ***
Bin: 150 count 13 ***
Bin: 151 count 12
Bin: 152 count 1 ***

Arduino Map Conclusion

Given it is such a pain to get working exactly right, its probably better to do one of the following.

• Don't worry about the error - its only small if the ouput mapped value is fairly large compared to the input  - but remember the last output value will only be generated once.
• Use a floating point calculation - but will be slower and use more memory.
  
• Avoid using map()  - For instance for an ADC conversion to 0 to 255 just use the upper 8 bits of the result - use function analogReadResolution() for this.
  

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